mathematically: e^(ln x) = x
in java:
Math.pow(Math.E, (Math.log(x)) == x; //equals true
题
can someone please tell me How to find antilog for a number using java program? i am new to this java
Math.log(10)
gives the log value. now I want to take this output and verify using antilog that program is giving right value.please help me.
解决方案
mathematically: e^(ln x) = x
in java:
Math.pow(Math.E, (Math.log(x)) == x; //equals true
其他提示
You can use Logarithm class in Java to calculate log and antilog. More on this is provided here.