Use the vectorized max
>>> map(max, abs(a[2]-a) )
[3, 4, 0]
>>> np.abs(a[2] - a).max(axis=1)
array([3, 4, 0])
题
This is the problem I have faced when I am writing python code for sample entropy.
map(max, abs(a[i]-a) )
is very slow.
Is there any other function perform better than map()
?
Where a
is ndarray that looks like np.array([ [1,2,3,4,5],[2,3,4,5,6],[3,4,5,3,2] ])
解决方案
Use the vectorized max
>>> map(max, abs(a[2]-a) )
[3, 4, 0]
>>> np.abs(a[2] - a).max(axis=1)
array([3, 4, 0])