用ColdFusion Orm在类型表中排序列
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08-10-2019 - |
题
我有三张桌子,具有以下结构:
http://dl.dropbox.com/u/2586403/ormissues/tablelelayout.png
我要处理的三个对象在这里:
http://dl.dropbox.com/u/2586403/ormissues/objects.zip
我需要能够获取一个partObject,然后拉出其所有属性,并由类型表中的属性元素排序。这是我遇到的问题:
我无法通过其属性为partoBject中的属性属性。AttributeName属性
我无法将attribute.attributename属性添加到objectAttribute实体中,因为我会遇到有关列名的错误。 Hibernate将ID放在联接的错误一侧
这是显示不良查询的冬眠日志文件
10/14 16:36:39 [jrpp-12] HIBERNATE DEBUG - select objectattr0_.ID as ID1116_, objectattr0_.AttributeValue as Attribut2_1116_, objectattr0_.AttributeID as Attribut3_1116_, objectattr0_1_.AttributeName as Attribut2_1117_ from ObjectAttributes objectattr0_ inner join Attributes objectattr0_1_ on objectattr0_.ID=objectattr0_1_.AttributeID
10/14 16:36:39 [jrpp-12] HIBERNATE ERROR - [Macromedia] [SQLServer JDBC Driver][SQLServer]Invalid column name 'AttributeID'.
10/14 16:36:39 [jrpp-12] HIBERNATE ERROR - [Macromedia] [SQLServer JDBC Driver][SQLServer]Statement(s) could not be prepared.
这是查询的有问题部分:
from ObjectAttributes objectattr0_
inner join Attributes objectattr0_1_ on objectattr0_.ID=objectattr0_1_.AttributeID
它应该是:
from ObjectAttributes objectattr0_
inner join Attributes objectattr0_1_ on objectattr0_.AttributeID=objectattr0_1_.ID
objectAttribute.cfc上的属性属性是引起问题的一种:
component output="false" persistent="true" table="ObjectAttributes"
{
property name="ID" column="ID" generator="native" type="numeric" ormtype="int" fieldtype="id" unsavedvalue="0" ;
property name="AttributeValue" type="string" ;
property name="Attribute" fieldtype="many-to-one" cfc="Attribute" fkcolumn="AttributeID" fetch="join";
property name="AttributeName" table="Attributes" joincolumn="AttributeID" ;
}
我还尝试使用一个公式在Objectattribute实体上获取属性,例如:
component output="false" persistent="true" table="ObjectAttributes"
{
property name="ID" column="ID" generator="native" type="numeric" ormtype="int" fieldtype="id" unsavedvalue="0" ;
property name="AttributeValue" type="string" ;
property name="Attribute" fieldtype="many-to-one" cfc="Attribute" fkcolumn="AttributeID" fetch="join";
property name="AttributeName" type="string" formula="(SELECT A.AttributeName FROM Attributes A WHERE A.ID = AttributeID)";
}
这有效,但是我无法按照计算的列进行排序。如果我然后调整partObject.cfc,则可以:
property name="Attributes" cfc="ObjectAttribute" type="array" fkcolumn="ObjectID" fieldtype="one-to-many" orderby="AttributeName";
我在HibernatesQL日志中获取以下错误:
10/17 16:51:55 [jrpp-0] HIBERNATE DEBUG - select attributes0_.ObjectID as ObjectID2_, attributes0_.ID as ID2_, attributes0_.ID as ID244_1_, attributes0_.AttributeValue as Attribut2_244_1_, attributes0_.AttributeID as Attribut3_244_1_, ((SELECT A.AttributeName FROM Attributes A WHERE A.ID = attributes0_.AttributeID)) as formula25_1_, attribute1_.ID as ID246_0_, attribute1_.AttributeName as Attribut2_246_0_ from ObjectAttributes attributes0_ left outer join Attributes attribute1_ on attributes0_.AttributeID=attribute1_.ID where attributes0_.ObjectID=? order by attributes0_.AttributeName
10/17 16:51:55 [jrpp-0] HIBERNATE ERROR - [Macromedia][SQLServer JDBC Driver][SQLServer]Invalid column name 'AttributeName'.
10/17 16:51:55 [jrpp-0] HIBERNATE ERROR - [Macromedia][SQLServer JDBC Driver][SQLServer]Statement(s) could not be prepared.
这是一个垃圾场 没有 该属性表明其余的关系正常运行:
http://dl.dropbox.com/u/2586403/ormissues/dump.pdf
我不知道如何解决此问题。您可以提供的任何帮助将不胜感激。
谢谢,
担
解决方案
我在Sam的帮助下解决了这一问题,通过在服务中设置一种方法,该方法按照我想要的顺序返回项目。我只是使用ormexecutequery以正确的顺序获取项目,如果没有项目,则返回一个空数组。
最终方法看起来像这样,其中规格按我想要的顺序直接设置在对象中:
/**
@hint Gets a SpecGroups object based on ID. Pass 0 to retrieve a new empty SpecGroups object
@ID the numeric ID of the SpecGroups to return
@roles Admin, User
*/
remote ORM.SpecGroups function getSpecGroup(required numeric ID){
if(Arguments.ID EQ 0){
return New ORM.SpecGroups();
}else{
LOCAL.SpecGroup = EntityLoadByPK("SpecGroups", Arguments.ID);
LOCAL.SpecsInGroup = ORMExecuteQuery("SELECT Spec FROM SpecInGroup G WHERE G.SpecGroupID = :GroupID ORDER BY SpecLabel, SpecName", {GroupID = LOCAL.SpecGroup.getID()});
LOCAL.SpecGroup.setSpecifications(LOCAL.SpecsInGroup);
return LOCAL.SpecGroup;
}
}