检查表格中的字段是否具有空间或逗号-MS -ACCESS

Question

我的表名为FinalForgotten，它仅包含一个名为Aname的字段。该领域可能看起来像史密斯·约翰（Smith John）或史密斯（John）。因此，最后一个名字和名字都在同一字段中，并由空间或逗号界定。防御字段包含三个字段：first_name，last_name，middle_initial。 First_name字段将包含与ANAME字段（例如John）中的数据完全匹配的数据。 last_name字段将包含与ANAME字段（例如Smith）中完全匹配数据的数据。我试图将所有最终孔的Aname记录带入新桌子（例如Smith，John S）。防御表是该中间缩写的原因。

这将有效：

SELECT left([aname],InStr(1,[aname],",")-1) & " "& right([aname],Len(aname)-InStr(1,[aname],",")) & " "& summary_judgment.middle_initial AS fullnameINTO FinalForgottenWithMiddle FROM FinalForgotten INNER JOIN summary_judgment ON((left(FinalForgotten.aname,InStr(1,FinalForgotten.[aname],",")-1))=summary_judgment.last_name) AND((right(FinalForgotten.aname,Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],","))=summary_judgment.first_name));

但是，如果Final -Forgotten包含一个没有逗号的字段，则会返回“无效的程序调用”，例如：Smith John。

因此，为了解决这个问题，我试图考虑逗号是否在现场：

SELECT left([aname], IIF(instr([aname], ",") = 0, InStr(1,[aname]," ")-1),InStr(1,[aname],",")-1)  &  ", "  & right([aname], IIF(instr([aname], ",") = 0,Len(aname)-InStr(1,[aname]," "),Len(aname)-InStr(1,[aname],",") &  " " & defense_final.middle_initial AS fullname INTO FinalForgottenWithMiddle
FROM FinalForgotten INNER JOIN defense_final ON 
((right(FinalForgotten.aname,IIF(instr([aname], ",") = 0,Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," ")),Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],","))=defense_final.first_name)) 
AND 
((left(FinalForgotten.aname,,IIF(instr([aname], ",") = 0,InStr(1,FinalForgotten.[aname]," ")-1)),InStr(1,FinalForgotten.[aname],",")-1))=defense_final.last_name);

这给我带来了“丢失的操作员语法”错误，并突出显示了该词。

感谢您的回复。

Answer 1

似乎有很多缺失的括号。

SELECT left(
      [aname], 
      IIF(instr([aname], ",") = 0,
        InStr(1,[aname]," ")-1,
        InStr(1,[aname],",")-1
        ) 
      )
    &  ", "  & 
    right(
       [aname], 
       IIF(instr([aname], ",") = 0,
         Len(aname)-InStr(1,[aname]," "),
         Len(aname)-InStr(1,[aname],",") 
         )
        )
     &  " " & 
    defense_final.middle_initial AS fullname 
INTO FinalForgottenWithMiddle
FROM FinalForgotten
INNER JOIN defense_final 
ON 

    right(FinalForgotten.aname,
     IIF(instr([aname], ",") = 0,
     Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," "),
     Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],",")
      )
     )=defense_final.first_name

AND 

   left(FinalForgotten.aname,
    IIF(instr([aname], ",") = 0,
      InStr(1,FinalForgotten.[aname]," ")-1,
      InStr(1,FinalForgotten.[aname],",")-1
        )
    )=defense_final.last_name