In Fortran 95 you can't "pass" allocatable arrays as an allocatable thing to anything, including Fortran procedures.
In Fortran 2003, the C function can malloc storage for the array, and then return that to the Fortran side as a C_PTR from the ISO_C_BINDING intrinsic module. The storage pointed to by the C_PTR can then be accessed using a Fortran POINTER and the C_F_POINTER procedure from the ISO_C_BINDING module.
To free the storage for the array, the Fortran side would again call into a C procedure, passing the C_PTR, which the C function then uses in a call to free.
#include "stdlib.h"
int *create_storage()
{
/* Array of four integers. */
return malloc(sizeof(int) * 4);
}
void destroy_storage(int *ptr)
{
free(ptr);
}
PROGRAM fortran_side
USE, INTRINSIC :: ISO_C_BINDING, ONLY: C_PTR, C_F_POINTER, C_INT
IMPLICIT NONE
INTERFACE
FUNCTION create_storage() BIND(C, NAME='create_storage')
USE, INTRINSIC :: ISO_C_BINDING, ONLY: C_PTR
IMPLICIT NONE
TYPE(C_PTR) :: create_storage
END FUNCTION create_storage
SUBROUTINE destroy_storage(p) BIND(C, NAME='destroy_storage')
USE, INTRINSIC :: ISO_C_BINDING, ONLY: C_PTR
IMPLICIT NONE
TYPE(C_PTR), INTENT(IN), VALUE :: p
END SUBROUTINE destroy_storage
END INTERFACE
TYPE(C_PTR) :: p
INTEGER(C_INT), POINTER :: array(:)
!****
p = create_storage()
CALL C_F_POINTER(p, array, [4]) ! 4 is the array size.
! Work with array...
CALL destroy_storage(p)
END PROGRAM fortran_side
In Fortran 201X, C header files and functions may be provided to allow C to work directly with Fortran allocatable variables.