select SUBSTRING_INDEX(supplier_reference,'=',-1) from ps_product;
Please use this for further reference.
Frage
I need to extract everything after the last '=' (http://www.domain.com?query=blablabla - > blablabla) but this query returns the entire strings. Where did I go wrong in here:
SELECT RIGHT(supplier_reference, CHAR_LENGTH(supplier_reference) - SUBSTRING('=', supplier_reference))
FROM ps_product
Lösung
select SUBSTRING_INDEX(supplier_reference,'=',-1) from ps_product;
Please use this for further reference.
Andere Tipps
Try this (it should work if there are multiple '=' characters in the string):
SELECT RIGHT(supplier_reference, (CHARINDEX('=',REVERSE(supplier_reference),0))-1) FROM ps_product
Try this in MySQL.
right(field,((CHAR_LENGTH(field))-(InStr(field,','))))
In MySQL, this works if there are multiple '=' characters in the string
SUBSTRING(supplier_reference FROM (LOCATE('=',supplier_reference)+1))
It returns the substring after(+1) having found the the first =
I've been working on something similar and after a few tries and fails came up with this:
Example: STRING-TO-TEST-ON = 'ab,cd,ef,gh'
I wanted to extract everything after the last occurrence of "," (comma) from the string... resulting in "gh".
My query is:
SELECT SUBSTR('ab,cd,ef,gh' FROM (LENGTH('ab,cd,ef,gh') - (LOCATE(",",REVERSE('ab,cd,ef,gh'))-1)+1)) AS `wantedString`
Now let me try and explain what I did ...
I had to find the position of the last "," from the string and to calculate the wantedString length, using LOCATE(",",REVERSE('ab,cd,ef,gh'))-1
by reversing the initial string I actually had to find the first occurrence of the "," in the string ... which wasn't hard to do ... and then -1 to actually find the string length without the ",".
calculate the position of my wantedString by subtracting the string length I've calculated at 1st step from the initial string length:
LENGTH('ab,cd,ef,gh') - (LOCATE(",",REVERSE('ab,cd,ef,gh'))-1)+1
I have (+1) because I actually need the string position after the last "," .. and not containing the ",". Hope it makes sense.
I haven't tested the query on large strings so I do not know how slow it is. So if someone actually tests it on a large string I would very happy to know the results.
If your string is
str = 'abc=def=ghi'
To select to the right:
select substring_index(str,'=',-1) from tablename ==> result is 'ghi'
select substring_index(str,'=',-2) from tablename ==> result is 'def=ghi'
To select to the left
select substring_index(str,'=',-1) from tablename ==> result is 'abc'
select substring_index(str,'=',2) from tablename ==> result is 'abc=def'
For SQL Management studio I used a variation of BWS' answer. This gets the data to the right of '=', or NULL if the symbol doesn't exist:
CASE WHEN (RIGHT(supplier_reference, CASE WHEN (CHARINDEX('=',supplier_reference,0)) = 0 THEN
0 ELSE CHARINDEX('=', supplier_reference) -1 END)) <> '' THEN (RIGHT(supplier_reference, CASE WHEN (CHARINDEX('=',supplier_reference,0)) = 0 THEN
0 ELSE CHARINDEX('=', supplier_reference) -1 END)) ELSE NULL END