Perl : get path of the file in a directory [closed]

Question

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.

---

This question appears to be off-topic because it lacks sufficient information to diagnose the problem. Describe your problem in more detail or include a minimal example in the question itself.

Closed 8 years ago.

Improve this question

I open a directory a/b/c/

c has d1 , d2, d3 d4

I wanna print the path of d1 d2 d3 d4

like

a/b/c/d1
a/b/c/d2
a/b/c/d3 and soo on

Answer 1

you can try Cwd

perl -e 'use Cwd 'abs_path'; print abs_path("myfile");'

Answer 2

use Cwd 'abs_path';

print "$_\n" for map abs_path($_), glob("a/b/c/*");

Answer 3

Unless you want to canonize the path for prettyness (in which case you want File::Spec->canonpath and not Cwd::abs_path), you can simply use

"$dir/$fn"