Frage

i wrote simple arduino program to check a an array of ascii characters. Here is the program

void setup(){
  Serial.begin(9600); // connect serial

}

void loop(){

char inByte;
  char arr[100]={0};
  char arrr[5]={'s','t','a','r','t'};
 int x=0;
 int y=0;
  do{

    arr[x]=arrr[y];
    x++;
    y++;
      }while(arr[0]!='s' && arr[1] !='t' && arr[2]!='a' && arr[3]!='r' && arr[4]!='t');
  if(arr[0]=='s' && arr[1] =='t' && arr[2]=='a' && arr[3]=='r' && arr[4]=='t'){
    delay(1000);
    Serial.println("done");}
    else{
    delay(1000);
    Serial.println("oo");
}

}

I want it to show "done" in serial monitor but instead it is printing "oo"..can any one tell me what is the problem in the program..thanks

Keine korrekte Lösung

Andere Tipps

open braces for else part also

if(arr[0]=='s' & arr[1] =='t' & arr[2]=='a' & arr[3]=='r' & arr[4]=='t'){
    delay(1000);
    Serial.println("done");
}
else {
    delay(1000);
    Serial.println("oo"); 
}
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