Frage
I probably have been staring at this too long and am missing something obvious, but: why is this working fine in JSFiddle and NOT when I upload it??
The alert at the end is showing up on the test website, but the "showthis" is also visible no matter what.
HTML
https://stackoverflow.com/questions/22633560
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Russian<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Test Form Field</title>
<script type="text/javascript" src="scripts/jquery-1.11.0.min.js"></script>
<script type="text/javascript" src="scripts/showfield.js"></script>
</head>
<body>
<input type="checkbox" name="checkbox" id="checkbox" value="checkbox" />
<br />
<input id="showthis" name="showthis" size="50" type="text" value="text here"/>
</body>
</html>
jQuery (I've downloaded a minified jQuery 1.11.0 , which is what's working in JSFiddle)
//hide field by default
$('input[name="showthis"]').hide();
//show it when the checkbox is clicked
$('input[name="checkbox"]').on('click', function(){
if ( $(this).prop('checked') ) {
$('input[name="showthis"]').fadeIn();
}
else {
$('input[name="showthis"]').hide();
}
});
// the alert is showing fine
alert ("hello");
JSFiddle http://jsfiddle.net/DLQY9/
Lösung
Wrap your code in a loading event. This is the newer, preferred, syntax (rather than $(window) or $(document)):
$(function () {
$('input[name="showthis"]').hide();
//show it when the checkbox is clicked
$('input[name="checkbox"]').on('click', function () {
if ($(this).prop('checked')) {
$('input[name="showthis"]').fadeIn();
} else {
$('input[name="showthis"]').hide();
}
});
});
Andere Tipps
Try this
$(window).load(function(){
$('input[name="showthis"]').hide();
//show it when the checkbox is clicked
$('input[name="checkbox"]').on('click', function(){
if ( $(this).prop('checked') ) {
$('input[name="showthis"]').fadeIn();
}
else {
$('input[name="showthis"]').hide();
}
});
});
Other answers are good but there is a little problem in them. If you refresh page when checkbox checked, showthis will be hide because of first line :
$('input[name="showthis"]').hide();
So we need another condition before on click listener as follow :
$(function () {
if($('input[name="checkbox"]').prop('checked')){
$('input[name="showthis"]').fadeIn();
} else {
$('input[name="showthis"]').hide();
}
//show it when the checkbox is clicked
$('input[name="checkbox"]').on('click', function () {
if ($(this).prop('checked')) {
$('input[name="showthis"]').fadeIn();
} else {
$('input[name="showthis"]').hide();
}
});
});
