So, your interpreter doesn't have printf
after all? that's a shame. We can get the desired output by hand, it's a bit cumbersome but this should work on most Scheme interpreters, notice that an extra procedure is required for keeping track of the index:
(define lst
'(("001" "Bob" 80) ("002" "Sam" 85) ("003" "Aaron" 94)))
(define (add-index lst)
(let loop ((lst lst) (idx 1))
(if (null? lst)
'()
(cons (cons idx (car lst))
(loop (cdr lst) (+ idx 1))))))
(for-each (lambda (e)
(display "No.")
(display (car e))
(display ": ID=")
(display (cadr e))
(display ", Name=’’")
(display (caddr e))
(display "’’, Grade=")
(display (cadddr e))
(newline))
(add-index lst))
It prints the desired result:
No.1: ID=001, Name=’’Bob’’, Grade=80
No.2: ID=002, Name=’’Sam’’, Grade=85
No.3: ID=003, Name=’’Aaron’’, Grade=94