XML Parsing w/ Python Element Tree - Namespace sometimes not specified

Question

I'm trying to parse a number of xml files that only sometimes have xmlns set. Is there any way to determine whether it's set w/o using the lxml library?

My main issue is when finding elements using find or findall, nothing is returned if the namespace is set since the tag doesn't match. But I can't hardcode the namespace in because sometimes there is no namespace set. I don't really know how to go about this.

Here's a sample of some of my code

 tree = ET.parse(xml_file_path)
 root = tree.getroot() #ONIXmessage
 ...
 pids = product.findall("productidentifier")
 ...

So my main issue is with the findall() method

Thanks.

Answer 1

I will shortly be having this problem/question too. My thought was: use a wrapper function that first tries to get the elements without the namespace specified, and if that returns None, then try with the namespace. If both return None, then the elements were not present. Using both functions (without if-else) works nicely if no default namespace is provided.

If the choice is between the same namespace either being specified or not, then I think ths approach above is okay. If you have multiple-optional-namespaces, it will make your wrapper more complicated but it's a one-time effort.

Would like to see a more elegant solution for this though. Did DanielHaley's answer work?

Related options:

• There's also this answer to specify the namespace in find, findall, etc.
• Could try register_namespace as per the solution here, which works for writing out.
• This one suggests using * to find but that's too generic to use to find specific elements.
• Suppress namespaces altogether
• If desperate, you can try using regex

Answer 2

It's kind of a pain, but you could use local-name() in your XPath.

For example, instead of:

/foo/bar/baz

try:

/*[local-name()='foo']/*[local-name()='bar']/*[local-name()='baz']