run time error - non zero exception

Question

my programming teacher gave me this problem to code it in c : given array of N integers A and a number K. During a turn the maximal value over all Ai is chosen, let's call it MAX. Then Ai = MAX - Ai is done for every 1 <= i <= N. Help Roman to find out how will the array look like after K turns.

Input

The numbers N and K are given in the first line of an input. Then N integers are given in the second line which denote the array A.

Output

Output N numbers on a single line. It should be the array A after K turns.

Constraints

* 1 <= N <= 10^5
* 0 <= K <= 10^9
* Ai does not exceed 2 * 10^9 by it's absolute value.

Example

Input:
4 1
5 -1 7 0

Output:
2 8 0 7

and my code to this problem is :

#include<stdio.h>
#include<stdlib.h>
#include<math.h>


long int Max(long int *arr, int low, int high)
{
long int max,i;

max = arr[low];
for(i=0;i<=high;i++)
{
    if(max<=arr[i])
      max = arr[i];
}

  return max;
}

 /* Driver program to test above function */
 int main()
 {
    long int max,*arr;
    long int n,k,c1,c2,c3,i,j;

    c1 = (long int)pow(10,5);
    c2 = (long int)pow(10,9);
    c3 = 2*c2;
    scanf("%ld %ld",&n,&k);

    if(n<1||n>c1)
      exit(1);
    else if(k<0||k>c2)
      exit(1);
    else
    {
    arr = (long int *)malloc(sizeof(int)*n);
    for(i=0;i<n;i++)
      {
        scanf("%ld",&arr[i]);
        if(abs(arr[i])>c3)
          exit(1);
      }
    if(k%2 == 0)
      {
        for(i=0;i<2;i++)
        {
            max = Max(arr, 0, n-1);
            for(j=0;j<n;j++)
            {   
                arr[j] = max-arr[j];
                if(abs(arr[j])>c3)
                            exit(1);
            }
        }
      }
    else if(k%2 != 0)
    {
        max = Max(arr, 0, n-1);
                    for(j=0;j<n;j++)
                       {       
                        arr[j] = max-arr[j];
                            /*if(abs(arr[j])>c3)
                              exit(1);*/
                       }
    }
    /*  for(m=0;m<n;m++)
                printf("%ld ",arr[m]);
        printf("\n");*/

    for(i=0;i<n;i++)
      printf("%ld ",arr[i]);

    printf("\n");
   }  
   return 0;
 }

i executed this code on gcc compiler in ubuntu, it is working perfectly with all the constraints satisfied but when I uploaded this code on my teacher's portal which has a compiler and executed the code, it said Runtime error -

nzec which means a non-zero exception which is used to signify that main() does not have "return 0;" statement or exception thrown by c++ compiler.

Please, can anyone help me what is wrong in my code as there is a return 0; statement in my code. Please Help.

Everyone has pointed out multiple use of exits ... Can I reduce them using any other way in place of exit()?

Answer 1

My guess is that it has to do with the various exit(1) statements you have for error conditions.

Answer 2

As pointed out by Dave Costa, exit(1) could be the cause

Another possible problem is the size of the allocated array:

arr = (long int *)malloc(sizeof(int)*n);

should be:

arr = malloc(sizeof(long int)*n);

And note that you don't need to use pow for constants:

c1 = (long int)pow(10,5);
c2 = (long int)pow(10,9);

could be replaced with:

c1 = 1e5L;
c2 = 1e9L;