Convert a list to a data.frame in R

Question

Sample data:

ht <- list(c("word1","word2"),c("number1","number2"))

First, strsplit() requires comma, but I'm failing to insert comma between the strings.

I have tried something like;

lapply(ht, function(x) paste("",",",x) 

Anyway, the desired output:

  Words   Numbers
1 word1   number1 
2 word2   numner2

where Words and Numbers are column names.

EDIT: This is what I came up with, but in one column.

seplist <- lapply(splitString, function(x) paste(shQuote(x, type="cmd"), collapse=","))
unls <- data.table(unlist(seplist))
head(unls)

How could I proceed from here to the desired outcome?

EDIT 2: The data I have look like this:

      [[1]]
 [1] "WIELANDER, s.r.o."                       "Milochov 223  01706   Považská Bystrica"

[[2]]
 [1] "Vojenský technický ústav, a.s."          "kpt. Nálepku  03101   Liptovský Mikuláš"

[[3]]
 [1] "Property Service, s.r.o."   "Dlhá  25A  90031   Stupava"

Answer 1

Make use of the fact that a data.frame in R is a list of atomic vectors (each column = separate list item). This means that you almost have what you want.

structure(as.data.frame(ht), names=c('Words', 'Numbers'))
##   Words Numbers
## 1 word1 number1
## 2 word2 number2

Answer 2

> ht <- list(c("word1","word2"), c("number1","number2"))
> x <- data.frame(do.call(cbind, ht))
> names(x) <- c('Words', 'Numbers')
> x
  Words Numbers
1 word1 number1
2 word2 number2

Of course, this would be even more simple if ht was a named list.

> ht <- list(Words = c("word1","word2"), Numbers = c("number1","number2"))
> data.frame(do.call(cbind, ht))
  Words Numbers
1 word1 number1
2 word2 number2

Answer 3

With lapply,do.call and unlist

df<-do.call(cbind,lapply(ht,function(x) data.frame(x=unlist(x),stringsAsFactors=FALSE)))
names(df)<-c("Words","Numbers")
> df
  Words Numbers
1 word1 number1
2 word2 number2