You have not allocated any memory for str
. Declare a buffer, for example char str[50]
, but be aware of buffer overflows.
Frage
Working on this little piece of code, but for some reason it keep crashing the whole time.
Anyone got an idea what i'm doing wrong
char *str;
printf("Enter a string\n");
gets(str);
printf("The size of the string is %d", strlen(str));
system("PAUSE");
return 0;
Lösung
Andere Tipps
You only created an char* pointer which points to random space in memory and you try to do something with it - and that is why your program crashes.
You should create an array of chars:
char str[50];
or dynamically allocate memory for string with malloc:
char* str;
str = (char *)malloc(50*sizeof(char)); // allocate memory
// some operations
free(str); // deallocate memory
where 50 is your estimated size of buffer.
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