Ransack opposite predicate :present

Question

Ransack has abilities finding User that has a first_name:

User.search(:first_name_present => "1")

and the opposite, finding User with no first_name or blank:

User.search(:first_name_blank => "1")

.

Unfortunately,

User.search(:first_name_present => "0") not equal with

User.search(:first_name_blank => "1")

.

Is there anyway to make

User.search(:first_name_present => "0") equal

User.search(:first_name_blank => "1"),

or

User.search(:first_name_present => "1") equal

User.search(:first_name_blank => "0")?

Thx

Answer 1

You could of course do something like this before calling search:

params[:q][:first_name_present] = "1" if
  params[:q][:first_name_blank].nil? ||
  params[:q][:first_name_blank] == "0"

I think it's good that these are not the same thing, otherwise, you couldn't have a checkbox to only find those users with empty first name – it would not allow a state listing all users. As it is now, unchecked checkboxes do not cause filtering.