How to set the checkbox in the first column based on the value in the second column?

Question

I'm automating a task using Ruby and Watir.

I want to set a checkbox (which is in the first column of a table) based on whether the value in the second column matches my input value. For example, in the following code snippet, the value "brett58" matches my input value so I want to set the checkbox associated with it.

<tr class="cuesTableRowOdd">
    <td align="center">
        <input class="content-nogroove" type="checkbox" name="result[1].chked" value="true">
        <input type="hidden" value="7bd67e4d-a59f-0143-3886-22c1d205a5c1" name="result[1].col[0].stringVal">
        <input type="hidden" value="brett58" name="result[1].col[1].stringVal">
    </td>
    <td align="left">
        <a class="cuesTextLink" href="userEdit.do?key=7bd67e4d-a59f-0143-3886-22c1d205a5c1">brett58</a>
    </td>
    <td align="left">brett</td>
    <td align="left">lee</td>
    <td align="left"></td>
</tr>

But I'm unable to do it. In the above case, the following line serves the purpose (as my input value matches with that it first row):

browser.table(:class, "cuesTableBg").checkbox(:name, "result[1].chked").click

But it can't be used as the required value might not always be in the first row.

Looping through all the rows is one option but it's inefficient.

Answer 1

I would do:

browser.table(:class, "cuesTableBg").rows.find{ |row| 
  row.cells[1].text == 'brett58'
}.checkbox.set

Basically, this is saying find the first row of the table that has "brett58" in the second column. Then set the first checkbox in that row.

Answer 2

Try something like this:

def set_checkbox(row_text_to_match)
  @browser.table(:class, "cuesTableBg").row(:text, /#{Regexp.escape(row_text_to_match)}/).checkbox(:name, "result[1].chked").set
end