OK - Solution for my question 2 is here: I'm still working on fixing question 1.
http://scriptlerweb.appspot.com/script/show/102001
bulkDeleteJenkinsBuildsExceptOne_OfAGivenRelease.groovy
/*** BEGIN META {
"name" : "Bulk Delete Builds except the given build number",
"comment" : "For a given job and a given build numnber, delete all builds of a given release version (M.m.interim) only and except the user provided one. Sometimes a Jenkins job use Build Name setter plugin and same job generates 2.75.0.1 and 2.76.0.43",
"parameters" : [ 'jobName', 'releaseVersion', 'buildNumber' ],
"core": "1.409",
"authors" : [
{ name : "Arun Sangal" }
]
} END META **/
// NOTE: Uncomment parameters below if not using Scriptler >= 2.0, or if you're just pasting the script in manually.
// ----- Logic in this script takes 5000 as the infinite number, decrease / increase this value from your own experience.
// The name of the job.
//def jobName = "some-job"
// The release / version of a Jenkins job - i.e. in case you use "Build name" setter plugin in Jenkins for getting builds like 2.75.0.1, 2.75.0.2, .. , 2.75.0.15 etc.
// and over the time, change the release/version value (2.75.0) to a newer value i.e. 2.75.1 or 2.76.0 and start builds of this new release/version from #1 onwards.
//def releaseVersion = "2.75.0"
// The range of build numbers to delete.
//def buildNumber = "5"
def lastBuildNumber = buildNumber.toInteger() - 1;
def nextBuildNumber = buildNumber.toInteger() + 1;
import jenkins.model.*;
import hudson.model.Fingerprint.RangeSet;
def jij = jenkins.model.Jenkins.instance.getItem(jobName);
//def build = jij.getLastBuild();
println ""
println("- Jenkins Job_Name: ${jobName} -- Version: ${releaseVersion} -- Keep Build Number: ${buildNumber}");
println ""
println " -- Range before given build number: ${buildNumber}"
println ""
def setBuildRange = "1-${lastBuildNumber}"
def range = RangeSet.fromString(setBuildRange, true);
jij.getBuilds(range).each {
if ( it.getDisplayName().find(/${releaseVersion}.*/)) {
println " ## Deleting >>>>>>>>>: " + it.getDisplayName();
// Trying to find - how to NOT delete a build in Jenkins if it's marked as "keep this build forever". If someone has an idea, please update this script with a newer version in GitHub.
//if ( !build.isKeepLog()) {
it.delete();
//} else {
// println "build -- can't be deleted as :" + build.getWhyKeepLog();
//}
}
}
println ""
println " -- Range after given build number: ${buildNumber}"
println ""
setBuildRange = "${nextBuildNumber}-5000"
range = RangeSet.fromString(setBuildRange, true);
jij.getBuilds(range).each {
if ( it.getDisplayName().find(/${releaseVersion}.*/)) {
println " ## Deleting >>>>>>>>>: " + it.getDisplayName();
it.delete();
}
}
println ""
println("- Builds have been successfully deleted for the above mentioned release: ${releaseVersion}")
println ""
One can also call this script via a Jenkins job (requires 3 parameters as mentioned in the scriptler script) -OR call it from browser as well: using the following link:
http ://YourJenkinsServerName:PORT/job/Some_Jenkins_Job_That_You_Will_Create/buildWithParameters?jobName=Test_AppSvc&releaseVersion=2.75.0&buildNumber=15