Map over object preserving keys

Question

The map function in underscore.js, if called with a javascript object, returns an array of values mapped from the object's values.

_.map({one: 1, two: 2, three: 3}, function(num, key){ return num * 3; });
=> [3, 6, 9]

is there a way to make it preserve the keys? ie, I want a function that returns

{one: 3, two: 6, three: 9}

Answer 1

With Underscore

Underscore provides a function _.mapObject to map the values and preserve the keys.

_.mapObject({ one: 1, two: 2, three: 3 }, function (v) { return v * 3; });

// => { one: 3, two: 6, three: 9 }

DEMO

---

With Lodash

Lodash provides a function _.mapValues to map the values and preserve the keys.

_.mapValues({ one: 1, two: 2, three: 3 }, function (v) { return v * 3; });

// => { one: 3, two: 6, three: 9 }

DEMO

Answer 2

I managed to find the required function in lodash, a utility library similar to underscore.

http://lodash.com/docs#mapValues

_.mapValues(object, [callback=identity], [thisArg])

Creates an object with the same keys as object and values generated by running each own enumerable property of object through the callback. The callback is bound to thisArg and invoked with three arguments; (value, key, object).

Answer 3

var mapped = _.reduce({ one: 1, two: 2, three: 3 }, function(obj, val, key) {
    obj[key] = val*3;
    return obj;
}, {});

console.log(mapped);

<script src="http://underscorejs.org/underscore-min.js"></script>
<script src="https://getfirebug.com/firebug-lite-debug.js"></script>

Answer 4

How about this version in plain JS (ES6 / ES2015)?

let newObj = Object.assign(...Object.keys(obj).map(k => ({[k]: obj[k] * 3})));

jsbin

If you want to map over an object recursively (map nested obj), it can be done like this:

const mapObjRecursive = (obj) => {
  Object.keys(obj).forEach(key => {
    if (typeof obj[key] === 'object') obj[key] = mapObjRecursive(obj[key]);
    else obj[key] = obj[key] * 3;
  });
  return obj;
};

jsbin

Since ES7 / ES2016 you can use Object.entries instead of Object.keys like this:

let newObj = Object.assign(...Object.entries(obj).map(([k, v]) => ({[k]: v * 3})));

And since ES2019 you can use Object.fromEntries.

let newObj = Object.fromEntries(Object.entries(obj).map(([k, v]) => ([k, v * 3])))

Answer 5

I know this is old, but now Underscore has a new map for objects :

_.mapObject(object, iteratee, [context]) 

You can of course build a flexible map for both arrays and objects

_.fmap = function(arrayOrObject, fn, context){
    if(this.isArray(arrayOrObject))
      return _.map(arrayOrObject, fn, context);
    else
      return _.mapObject(arrayOrObject, fn, context);
}

Answer 6

I know it's been a long time, but still the most obvious solution via fold (aka reduce in js) is missing, for the sake of completeness i'll leave it here:

function mapO(f, o) {
  return Object.keys(o).reduce((acc, key) => {
    acc[key] = f(o[key])
    return acc
  }, {})
}

Answer 7

_.map returns an Array, not an Object.

If you want an object you're better off using a different function, like each; if you really want to use map you could do something like this:

Object.keys(object).map(function(value, index) {
   object[value] *= 3;
})

but that is confusing, when seeing map one would expect to have an array as result and then make something with it.

Answer 8

I think you want a mapValues function (to map a function over the values of an object), which is easy enough to implement yourself:

mapValues = function(obj, f) {
  var k, result, v;
  result = {};
  for (k in obj) {
    v = obj[k];
    result[k] = f(v);
  }
  return result;
};

Answer 9

const mapObject = (obj = {}, mapper) =>
  Object.entries(obj).reduce(
    (acc, [key, val]) => ({ ...acc, [key]: mapper(val) }),
    {},
  );

Answer 10

A mix fix for the underscore map bug :P

_.mixin({ 
    mapobj : function( obj, iteratee, context ) {
        if (obj == null) return [];
        iteratee = _.iteratee(iteratee, context);
        var keys = obj.length !== +obj.length && _.keys(obj),
            length = (keys || obj).length,
            results = {},
            currentKey;
        for (var index = 0; index < length; index++) {
          currentKey = keys ? keys[index] : index;
          results[currentKey] = iteratee(obj[currentKey], currentKey, obj);
        }
        if ( _.isObject( obj ) ) {
            return _.object( results ) ;
        } 
        return results;
    }
}); 

A simple workaround that keeps the right key and return as object It is still used the same way as i guest you could used this function to override the bugy _.map function

or simply as me used it as a mixin

_.mapobj ( options , function( val, key, list ) 

Answer 11

You can use _.mapValues(users, function(o) { return o.age; }); in Lodash and _.mapObject({ one: 1, two: 2, three: 3 }, function (v) { return v * 3; }); in Underscore.

Check out the cross-documentation here: http://jonathanpchen.com/underdash-api/#mapvalues-object-iteratee-identity

Answer 12

_.map using lodash like loop to achieve this

 var result={};
_.map({one: 1, two: 2, three: 3}, function(num, key){ result[key]=num * 3; });
console.log(result)

//output
{one: 1, two: 2, three: 3}

Reduce is clever looks like above answare

_.reduce({one: 1, two: 2, three: 3}, function(result, num, key) {
  result[key]=num * 3
  return result;
}, {});

//output
{one: 1, two: 2, three: 3}