Javascript function returns value.call another function according to first functions return value

Question

sorry this might not be new question but i am new to JS and i didnt get any specific examples for this.

function find(param){            
        $.each(array,function(i,elem){              
            if(elem.id==param){
                return i;
            }
        })
        return null;
    }
//after calling this function i want to perform actions based on result
$(document).on("click","#elem",function(){
      //want to make this part synchronous
      $.when(i=find(param1)).then(function{
      if(i==null)
          {//do something
          }
      else{//do something
          }
})
}

i want to perform actions based on return value of find function.and also the conditions should only be checked ater the find function is over.

Answer 1

Your find function will always return null.

$.each(array,function(i,elem){              
    if(elem.id==param){
        return i;   //this is each iteration callback scope not find function scope
    }
})

The find function should look like this:

function find(param){
    var matched=null;            
    $.each(array,function(i,elem){              
        if(elem.id==param){
            matched=i;
        }
    })
    return matched;
}

Hope this is helpful for you.