How to find duration of a video file using mediainfo in seconds or other formats?

Question

How can I find duration of a video file in miliseconds i.e. in integer in deterministic way. I have used ffprobe to get the duration but it doesn't give duration for all file formats.

Answer 1

Use the following commands:

i) To get the duration of video stream:

$ mediainfo --Inform="Video;%Duration%"  [inputfile]

ii) To get the duration of the media file:

$ mediainfo --Inform="General;%Duration%" [inputfile]

iii) To get the duration of audio stream only:

$ mediainfo --Inform="Audio;%Duration%" [inputfile]

iv) To get values of more than one parameter:

$ mediainfo --Inform="Video;%Width%,%Height%,%BitRate%,%FrameRate%" [inputfile]

Output would be something like this:

1280,720,3000000,30.0

Answer 2

As offered by iota to use mediainfo --Inform="Video;%Duration%" [inputfile], possible but returns weird results.

For example, for video with duration 31s 565ms the output of given command would be:

31565

It wasn't suitable for me and I came up to the following solution:

mediainfo --Inform="Video;%Duration/String3%" inputExample.webm

Returned value is:

00:00:31.565

After all, you could just format returned value with, let's say PHP, to convert it to seconds, e.g.:

$parsed = date_parse( '00:00:31.565' );
echo $parsed['hour'] * 3600 + $parsed['minute'] * 60 + $parsed['second'];

Example

Answer 3

we can also use ffmpeg to get the duration of any video or audio files.

To install ffmpeg follow this link

import subprocess
import re

process = subprocess.Popen(['ffmpeg',  '-i', path_of_media_file], stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
stdout, stderr = process.communicate()
matches = re.search(r"Duration:\s{1}(?P<hours>\d+?):(?P<minutes>\d+?):(?P<seconds>\d+\.\d+?),", stdout, re.DOTALL).groupdict()

print matches['hours']
print matches['minutes']
print matches['seconds']

Answer 4

I use the below command on my xubuntu machine and it does exactly what the OP wants to accomplish.

mediainfo --Output="Video;%Duration%\n" *.mp4 | awk '{ sum += $1 } END { secs=sum/1000; h=int(secs/3600);m=int((secs-h*3600)/60);s=int(secs-h*3600-m*60); printf("%02d:%02d:%02d\n",h,m,s) }'