If for each chromosome you evaluate 4 functions, then obviously you have a total of 4*400*100 evaluations.
What you might also want to consider is the running time of each of this evaluations, because if 3 of the functions run in O(n)
and the forth runs in O(n^2)
, the total running time will be bounded by O(number_of_gens*population_size*n^2)
, and will be only mildly affected by the other three functions in large problem instances.