Beginner Python: If-else statements, formatting errors

Question 1

Ok... Lots of problems here. Lets start with some basic syntax stuff.

First of all, you need to go back and look at how formatting works in Python. It works in spaces of four, which is the equivalent of 'tab' if you are in the right processor. When you are defining a function, everything that will be contained in that function should be AT LEAST 4 spaces out. in your function "getWordForTwoDigits()" you have this:

def getWordForTwoDigits(amount):
...
return ...

That return should be four spaces out (you did this for both of your functions, BTW).

Second, your else-if structure is screwy and unneeded. Instead of what you have now, just do this:

if TensAmount == 1:
    do something
elif TensAmount == 2:
    do something different

Then just add more 'elif's down to 9.

Also, you say

singlesWord = getWordForDigit(int(amount)%10)

but you never define that function.

For you actual question of how to separate the 196 and the 97, try something like this:

def splitter(num):
    sep=str(num).rsplit('.', 1)
    return sep

The 'rsplit' basically splits the string into two parts based on the char in the first param. It returns a list ["partone", "parttwo"], so you will need to extract the two parts of the list and convert them back to ints in your main code.

Hope that helps!

Question 2

For the purpose of your practice we adapted an existing nice solution ref for converting numbers to words as follows:

def numToWords(num,join=True):
    '''words = {} convert an integer number into words'''
    units = ['','one','two','three','four','five','six','seven','eight','nine']
    teens = ['','eleven','twelve','thirteen','fourteen','fifteen','sixteen', \
             'seventeen','eighteen','nineteen']
    tens = ['','ten','twenty','thirty','forty','fifty','sixty','seventy', \
            'eighty','ninety']
    thousands = ['','thousand','million','billion','trillion','quadrillion', \
                 'quintillion','sextillion','septillion','octillion', \
                 'nonillion','decillion','undecillion','duodecillion', \
                 'tredecillion','quattuordecillion','sexdecillion', \
                 'septendecillion','octodecillion','novemdecillion', \
                 'vigintillion']
    words = []
    if num==0: words.append('zero')
    else:
        numStr = '%d'%num
        numStrLen = len(numStr)
        groups = (numStrLen+2)/3
        numStr = numStr.zfill(groups*3)
        for i in range(0,groups*3,3):
            h,t,u = int(numStr[i]),int(numStr[i+1]),int(numStr[i+2])
            g = groups-(i/3+1)
            if h>=1:
                words.append(units[h])
                words.append('hundred')
            if t>1:
                words.append(tens[t])
                if u>=1: words.append(units[u])
            elif t==1:
                if u>=1: words.append(teens[u])
                else: words.append(tens[t])
            else:
                if u>=1: words.append(units[u])
            if (g>=1) and ((h+t+u)>0): words.append(thousands[g]+',')
    if join: return ' '.join(words)
    return words

#example usages:
print numToWords(0)
print numToWords(11)
print numToWords(110)
print numToWords(1001000025)
print numToWords(123456789012)

results:

zero
eleven
one hundred ten
one billion, one million, twenty five
one hundred twenty three billion, four hundred fifty six million, seven hundred
eighty nine thousand, twelve

Note that it works for integer numbers. Nevertheless it is trivial to divide a float number into two integer parts.

Question 3

use elif instead of

else:
if

It is quick fix. For, part to handle 11-19,before

tensAmount = int(amount) / 10

use

if 10<amount<20:
#your statements to handle 11-19
else:
#your regular statements to divide by 10 again

but I strongly suggest you to work with dictionary, to get you started like this.

singleDigitDict={1="one", 2="Two"}#fill up
wordSingleDigit=singleDigitDict[singleDigitAmount]