Question

I know about generic lambdas, and I know about variable templates, but, what does this do? Is it even allowed?

template<typename T>
auto f = [](auto a, T b){ /**/ };

If it's allowed, can it be used as expected? That is, as f<type>(var_a, var_b)?

Was it helpful?

Solution

A variable template must be declared constexpr. A lambda cannot occur in a constant-expression, so the initialisation is not allowed, and its operator() is not declared constexpr, so calling it isn't allowed.

In summary, this is ill-formed in the current C++14 draft.

Note: curiously, even though a lambda-expression cannot occur in a constant-expression, it seems that the closure type of a lambda may have a constexpr copy/move constructor.

OTHER TIPS

This code is legal in the current draft of C++14 now and it compiles fine with clang 3.5 trunk

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