mySQL PHP WHERE IN returns a table- How do I parse this table?

Question

How do I use the data returned by a SQL WHERE IN(x,y) statement with PHP?

                $sqlquery = "SELECT * FROM schedules WHERE userid IN ('35','101','45')";

                if ($test_stmt=$mysqli->prepare($sqlquery)) { //Get all data in schedule row
                    $test_stmt->execute(); //Execute the prepared query
                    $test_stmt->store_result(); //Store result
                    $test_stmt->fetch();
                    do something...

                }
                else {
                    return null;
                }

            }

The SQL query returns the correct three table rows, I'm just not sure how to access them with PHP.

How do I create an array to store the values the query returns? Or is there a better way to store this data to later be manipulated?

Thanks

Answer 1

The most common way to do this is through a loop akin to the following:

$results=array();
while($row=$test_stmt->fetch())
{
    $results[]=$row;
}

This inserts the row into the results variable, which is an array. At the end of the loop, the array will contain a copy of everything the query returned.

You can also pick and choose what you do with particular columns in the results like this:

$results=array();
while($row=$test_stmt->fetch())
{
    $results[]['ID']=$row['ID'];
}

This assumes there is a column called "ID" in the results though.

Answer 2

//$test_stmt->store_result(); //not needed
$rows = $test_stmt->fetchAll(PDO::FETCH_ASSOC); //or other fetch mode

print_r($rows);  //$rows is an array of rows you can loop through