Calling Python script from another and passing List(sys.argv) as argument

Question

test1.py is the main script calling another script test2.py by passing the same argument list that has been passed to test1.py. I have done following but it reads the sys.argv list as string and parse into multiple arguments and also includes unnecessary [ and ,

test1.py
import os
import sys

argList=sys.argv[1:]

os.system('python another/location/test2.py %s'%(argList))

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test2.py

import sys
print(sys.argv[1:])

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Call test1.py
python test1.py -a -b -c
output: ['[-a,' ,'-b,', '-c]' ]

Please post if there is a better opti

Answer 1

Use

os.system('python another/location/test2.py %s' % ' '.join(argList))

if the arguments will contain no spaces themselves.

The second program will output

['-a', '-b', '-c']

If your arguments can contain spaces, it might be best to quote them. Use ' '.join("'%s'" % arg.replace("'", "\\'") for arg in ArgList)

Answer 2

in the case if you need to exit test1.py just after calling test2.py

import subprocess
subprocess.Popen( ('python', 'another/location/test2.py') + tuple( sys.argv[1:]) )