R: extract values of one column (x) that have at least one +1 in another column (y) in a data frame [closed]

Question

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.

---

Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist

Closed 8 years ago.

Improve this question

I have this data.frame:

> d
   x  y
1  6  1
2  2 -1
3  3 -1
4  2 -1
5  3  1
6  1 -1
7  4  1
8  7 -1
9  3 -1
10 4 -1
11 8  1
12 4 -1
13 2 -1
14 9 -1
15 5  1
16 7  1
17 6 -1
18 7 -1
19 3 -1
20 2 -1

I want to search for rows that have the same value in column1 and none of them have +1 in column 2. So, in this case, for example, rows that have value x=2 have no y=1, so I want to remove them. same thing also happens for rows with x=9 and x=1.

In another word, if we create subsets of the data by which in each subset, all the x values are the same, then any subset that doesn't have y=1 should be discarded.

Do you have any suggestion? If it is not clear, I will try to elaborate better!

Answer 1

I think this is what you want:

d[d$x %in% subset(aggregate(y ~ x, d, max), y == 1)$x, ]

---

For each unique x, get the maximum value:

aggregate(y ~ x, d, max)

Just return those x for which the maximum value of y is one.

subset(aggregate(y ~ x, d, max), y == 1)$x

And now pull out the rows where x is in that group of x values.

d[d$x %in% subset(aggregate(y ~ x, d, max), y == 1)$x, ]

Answer 2

Here is a simple solution:

>df[with(df,x %in% unique(x[y==1])),]
   x  y
1  6  1
3  3 -1
5  3  1
7  4  1
8  7 -1
9  3 -1
10 4 -1
11 8  1
12 4 -1
15 5  1
16 7  1
17 6 -1
18 7 -1
19 3 -1

Or, equivalently: df[df$x %in% unique(df$x[df$y==1]),]

Answer 3

This would be the test for the eventuality that d$y contains a value of 1 in any of the rows where d$x==2:

 any( d[d$x==2, "y"] == 1 )

If that eventuality holds, then return a dataframe that has removed all the d$x==2 rows using some Boolean algebra and logical indexing:

 d[ !as.logical( d$x == 2 * any( d[d$x==2, "y"] == 1 ) ) , ]

(Note: the value of 2 did not meet the narrow condition you set.)

If you wanted to apply that rule to all the unique values of d$x and apply a more general exclusionary condition of no y > 0

 lmat <- t( sapply( unique(d$x) , function(val) 
           as.logical( d[["x"]] == val * any( d[d[["x"]]==val, "y"] > 1 ) ) ) )
 # Now use `any` to determine which rows to exclude.
# One does need to transpose that matrix of excluded logicals.
 d[ ! apply( t(lmat) , 1, any), ]
   x  y
2  2 -1
4  2 -1
6  1 -1
13 2 -1
14 9 -1
20 2 -1

Answer 4

Wouldn't it be simpler to first find y==1 then check for duplicated x?

as.data.table(d)[y==1][x %in% x[duplicated(x)]]