Question

I am making this simple Windows forms app in Visual studio in c#. I have two forms. On form1 I have a textbox,listbox and two buttons (one to insert into listbox from textbox and another to open form2). On form2 I only have a textbox. I just simply want, when click on a button (for opening form2) on form1, form2 to open and textbox to contain (on formLoad) selected item from listbox from form1. But when I click on button it says "Object reference not set to an instance of an object". What am I doing wrong? I am pretty sure it's something simple but I just can't get it.

Thanks in advance!

Here is my code:

on form1:

  public partial class Form1 : Form
  {
    public Form1()
    {
        InitializeComponent();
    }

    private void btnOpenForm2_Click(object sender, EventArgs e)
    {
        Form2 f2 = new Form2();
        f2.ShowDialog();
    }

    private void button1_Click(object sender, EventArgs e)
    {
        listBox1.Items.Add(textBox1.Text);
    }
    public string Transfer
    {
        get { return listBox1.SelectedItem.ToString(); }
    }

and on form2:

 public partial class Form2 : Form
  {
    public Form2()
    {
        InitializeComponent();
    }

    private void Form2_Load(object sender, EventArgs e)
    {
        Form1 f1 = new Form1();
        textBox1.Text = f1.Transfer;
    }
Was it helpful?

Solution

Because in the Form2_Load event you always create a new instance of Form1 and then access the Transfer property which accesses listBox1.SelectedItem which is not set for the newly created form.

You should rather pass a referece to form 1 in the button event:

on form1:

private void btnOpenForm2_Click(object sender, EventArgs e)
{
    Form2 f2 = new Form2(this);
    f2.ShowDialog();
}

and on form2:

public partial class Form2 : Form
{
   Form1 f1;
   public Form2(Form1 f1)
   {
       this.f1 = f1;
       InitializeComponent();
   }

   private void Form2_Load(object sender, EventArgs e)
   {
       textBox1.Text = this.f1.Transfer;
   }
}

OTHER TIPS

In your Form2_Load method, you're creating a new instance of the object Form1, separate from your existing item.

Instead, you need to either: a) Pass a reference to your current Form1 object to Form2, so that Form2 can access the Transfer property. or b) Add a new property to Form2 (called Transfer, say), and then when you create Form2, assign the current textbox value to this property, like so:

Form2 f2 = new Form2();
f2.Transfer = listBox1.SelectedItem.ToString();
f2.ShowDialog();

You could also do this by adding a parameter to the constructor of Form2, although that's really a design decision.

because you haven't selected your listbox item,value listBox1.SelectedItem is null.Practice doing try catch block

You are creating new Form1 instance here, which is not related to Form1 instance which you used to open Form2:

private void Form2_Load(object sender, EventArgs e)
{
    Form1 f1 = new Form1(); // here is new instance of Form1 created
    textBox1.Text = f1.Transfer;
}

So, this new Form1 instance does not have selected item and you have error. I suggest you to pass selected item value to Form2 when you opening Form2:

private void btnOpenForm2_Click(object sender, EventArgs e)
{
    Form2 f2 = new Form2(Transfer); // pass selected item value to constructor
    f2.ShowDialog();
}

All you need is changing Form2 constructor to accept this string:

public Form2(string transfer)
{
    InitializeComponent();
    textBox1.Text = transfer;
}
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