Android PopupWindow prevent dissmis on anchor click

Question

I have a popupWindow that showAsDropDown on button click and this popupWindow has setOutsideTouchable(true) and I want to toggle show the popup when I click on my button but also to dismiss when I click outside of popup. The problem is that outside touch is called before button click and my popup is hide and show after that. Is there a way to do that ?

FIXED!!!

I figured out that the problem was that my popupwindow was not focused and I have to call

popupWindow.setFocusable(true);

to fix it.

Answer 1

If i understand in a correct way,

// Pop up Window showing

    LayoutInflater layoutInflater = (LayoutInflater) getBaseContext()
            .getSystemService(LAYOUT_INFLATER_SERVICE);
    popupView = layoutInflater.inflate(R.layout.menu_popup, null);
    popupWindow = new PopupWindow(popupView, LayoutParams.WRAP_CONTENT,
            LayoutParams.WRAP_CONTENT);
    popupWindow.setOutsideTouchable(true);

 // Add setBackgroundDrawable to the pop up window to close the dialog :

        popupWindow.setBackgroundDrawable(getResources().getDrawable(
            android.R.color.transparent));
    popupWindow.setTouchable(true);

using the following check, you can show the pop up as you desired

findViewById(R.id.topMenu).setOnClickListener(
            new View.OnClickListener() {

                @Override
                public void onClick(View v) {
                    // TODO Auto-generated method stub

                        popupWindow
                                .showAsDropDown(findViewById(R.id.topMenu));

            });

I have checked this. It is working fine.