Python, how can I print the current datetime on the same line as a text message?

Question

First experiences with Python here, I want to be able to print out some text with the current time/date as the first item on the line.

This is what I've been able to cook up so far, but it appears I'm syntactically incorrect, can someone please correct me?

import socket
import sys
import time
import datetime

remote_host = "127.0.0.1"

now = datetime.datetime.now()

for remote_port in [9002,8080]:
        now_text = now.strftime("%Y-%m-%d %H:%M")
        sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
        sock.settimeout(60)
        try:
                sock.connect((remote_host, remote_port))
        except Exception,e:
                print "%d %d closed " % now_text remote_port
        else:
                print  "%d %d open" % now_text remote_port
        sock.close()

Kind regards

Answer 1

I think you're looking for something like

print "%d %d closed" % (now_text, remote_port)

For future reference, here's one way to do that in Python 3:

print("{0} {1} closed".format(now_text, remote_port))

The .format() method was introduced in Python 2.6.

Answer 2

Two possible errors (the second one definite):

1. Exception,e needs to be replaced by Exception as e (depending on the Python version).
2. The % operator requires a tuple argument: "%d %d closed" % (a, b).

Answer 3

>>> print "%s %d closed " % (now_text,remote_port)
2011-03-15 14:46 9002 closed

Answer 4

This is my take:

#the code below will print the date and time on separate lines.

from datetime import datetime
now =datetime.now()

print('%s/%s/%s' %(now.month,now.day,now.year))
print('%s:%s:%s' %(now.hour,now.minute,now.second))