You could try the igraph
library. I'm not familiar with it, but i find this question interesting enough to code up an answer, so here we go:
Because you've got a directed network (senders and receivers) you're going to need to two measures of centrality: indegree and outdegree.
Calculating this is fairly simple, the complication is splitting by time points. So for each time point we need to do the following:
- Create an adjacency matrix indicating for each row (sender) the number of connections to each column (receiver).
- From that we can simply add up the connections in the rows to get the outdegree, and the connections in the columns for the indegree.
Assuming your data is stored in a data.frame
named df
we can use split
to split your data.frame
by time point:
nodes <- unique(c(unique(df$Sender), unique(df$Receiver)))
centrality <- lapply(split(df, df$Time), function(time.df) {
adj <- matrix(0, length(nodes), length(nodes), dimnames=list(nodes, nodes))
for (i in 1:nrow(time.df)) {
sender <- time.df[i, "Sender"]
receiver <- time.df[i, "Receiver"]
adj[sender, receiver] <- adj[sender, receiver] + 1
}
list(indegree=colSums(adj), outdegree=rowSums(adj))
})
names(centrality) <- paste0("Time.Point.", 1:length(centrality))
If we run the code on your data (I've replaced the Senders and Receivers with letters for clarity):
> centrality
$Time.Point.1
$Time.Point.1$indegree
a b c
0 1 1
$Time.Point.1$outdegree
a b c
2 0 0
$Time.Point.2
$Time.Point.2$indegree
a b c
2 0 0
$Time.Point.2$outdegree
a b c
0 2 0
$Time.Point.3
$Time.Point.3$indegree
a b c
0 2 0
$Time.Point.3$outdegree
a b c
2 0 0