Maybe do you need something similar?
$html = 'xxx:yyyimage_17aaa:9999';
$webwords = preg_split("/([:'\n\"]+|image_17)/", $html);
print_r($webwords);
And the output:
Array
(
[0] => xxx
[1] => yyy
[2] => aaa
[3] => 9999
)
Question
I am new to PHP regular expression syntax. Using the following two lines, I was able to phrase a website depending on the following characters :
’
newline
”
$html = @file_get_contents("http://news.yahoo.com");
$webwords = preg_split("/[:'\n\"]+/", $html);
Above code will only allow me to phrase a website depending on individual characters. Can you please tell me how I can parse a website with word phrases
? For example, above individual characters alone with the word image_17
$webwords = preg_split("/[:'\n\"]+ | (image_17) /", $html); ??
Solution
Maybe do you need something similar?
$html = 'xxx:yyyimage_17aaa:9999';
$webwords = preg_split("/([:'\n\"]+|image_17)/", $html);
print_r($webwords);
And the output:
Array
(
[0] => xxx
[1] => yyy
[2] => aaa
[3] => 9999
)