Can a CryptoStream leave the base Stream open?

Question

I create a MemoryStream, pass it to CryptoStream for writing. I want the CryptoStream to encrypt, and leave the MemoryStream open for me to then read into something else. But as soon as CryptoStream is disposed, it disposes of MemoryStream too.

Can CryptoStream leave the base MemoryStream open somehow?

using (MemoryStream scratch = new MemoryStream())
{
    using (AesManaged aes = new AesManaged())
    {
        // <snip>
        // Set some aes parameters, including Key, IV, etc.
        // </snip>
        ICryptoTransform encryptor = aes.CreateEncryptor();
        using (CryptoStream myCryptoStream = new CryptoStream(scratch, encryptor, CryptoStreamMode.Write))
        {
            myCryptoStream.Write(someByteArray, 0, someByteArray.Length);
        }
    }
    // Here, I'm still within the MemoryStream block, so I expect
    // MemoryStream to still be usable.
    scratch.Position = 0;    // Throws ObjectDisposedException
    byte[] scratchBytes = new byte[scratch.Length];
    scratch.Read(scratchBytes,0,scratchBytes.Length);
    return Convert.ToBase64String(scratchBytes);
}

Answer 1

You can but you will not be able to use using statements. You will need to manually manage the disposing of the object and you will also need to call FlushFinialBlock() to make sure all the data was written out to the underlying stream before working on it.

Once all you are done working with the stream you can then dispose all of the resources you where waiting on in the finally block at the end.

MemoryStream scratch = null;
AesManaged aes = null;
CryptoStream myCryptoStream = null;
try
{
    scratch = new MemoryStream();
    aes = new AesManaged();

    // <snip>
    // Set some aes parameters, including Key, IV, etc.
    // </snip>
    ICryptoTransform encryptor = aes.CreateEncryptor();
    myCryptoStream = new CryptoStream(scratch, encryptor, CryptoStreamMode.Write);
    myCryptoStream.Write(someByteArray, 0, someByteArray.Length);

    //Flush the data out so it is fully written to the underlying stream.
    myCryptoStream.FlushFinalBlock();

    scratch.Position = 0; 
    byte[] scratchBytes = new byte[scratch.Length];
    scratch.Read(scratchBytes,0,scratchBytes.Length);
    return Convert.ToBase64String(scratchBytes);
}
finally
{
    //Dispose all of the disposeable objects we created in reverse order.

    if(myCryptoStream != null)
        myCryptoStream.Dispose();

    if(aes != null)
        aes.Dispose();

    if(scratch != null)
        scratch.Dispose();
}

Answer 2

As of .NET 4.7.2, there is a second constructor with an added bool parameter called leaveOpen. If this is set to true then the CryptoStream's dispose method will not call dispose on the underlying stream.

Additionally, the other constructor without the leaveOpen parameter simply forwards the parameters to the new constructor with leaveOpen set to false.

MSDN
CryptoStream.Dispose(bool disposing)

Answer 3

As a second solution, you can make a WrapperStream object that simply passes every call along except for Dispose / Close. Make a wrapper around your memory stream, hand the wrapper to the crypto stream, and now closing the crypto stream does not touch the memory stream.

Answer 4

My simple solution:

class NotClosingCryptoStream : CryptoStream
{
    public NotClosingCryptoStream( Stream stream, ICryptoTransform transform, CryptoStreamMode mode )
        : base( stream, transform, mode )
    {
    }

    protected override void Dispose( bool disposing )
    {
        if( !HasFlushedFinalBlock )
            FlushFinalBlock();

        base.Dispose( false );
    }
}

Answer 5

It turns out, there isn't any need to break apart the using {} block into try{}finally{} ... Ultimately, you just have to use FlushFinalBlock() inside the using statement, and nest anything else inside there as necessary.

using (MemoryStream scratch = new MemoryStream())
{
    using (AesManaged aes = new AesManaged())
    {
        // <snip>
        // Set some aes parameters, including Key, IV, etc.
        // </snip>
        ICryptoTransform encryptor = aes.CreateEncryptor();
        using (CryptoStream myCryptoStream = new CryptoStream(scratch, encryptor, CryptoStreamMode.Write))
        {
            myCryptoStream.Write(someByteArray, 0, someByteArray.Length);
            myCryptoStream.FlushFinalBlock();
            scratch.Flush();   // not sure if this is necessary
            byte[] scratchBytes = scratch.ToArray();
            return Convert.ToBase64String(scratchBytes);
        }
    }
}