Can I truncate decimals in Java? [duplicate]

Question

This question already has answers here:

How can I truncate a double to only two decimal places in Java? (17 answers)

Closed 8 years ago.

I have this code:

import java.util.Scanner;

public class DecimalPoints {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) 
    {
        Scanner scanner = new Scanner(System.in);

        System.out.println("a: ");               // printing output
        String text_1 = scanner.nextLine();      // taking input
        double d1 = Double.parseDouble(text_1);  // parsing double from input  

        System.out.println("b: ");               // printing output
        String text_2 = scanner.nextLine();      // taking input
        double d2 = Double.parseDouble(text_2);  // parsing double from input

        double d3 = d1 / d2;

        d3 = Math.round(d3 * 100) / 100.0d;

        System.out.println("Result: " + d3);
    }
}

It takes two inputs and rounds it up to two decimal places but the problem is that it rounds up the result. Let's say that I enter a = 513 and b = 791 the result would be 0.65 but when I check my calculator it shows me 0.648...Does anyone know how to leave the number just at 0.64? Much Obliged.

Answer 1

Maybe use Math.floor() instead of Math.round()?

Answer 2

Check out java.math.BigDecimal.