UCSR2C |= (1<<USBS2)|(1<<UCSZ21)|(1<<UCSZ20);
USBS2 sets 2 stop bits. Is this intentional?
void USART2Write(char data){
while( !(UCSR2A & (1<<UDRE2)));
UCSR2B &= ~(1<<TXB82); //in the case if there are more than 8 bits of data
if(data & 0x100) {
UCSR2B |= (1 << TXB82);
}
UDR2 = data;
}
If you really want to use 9 data bits, UCSZ22, UCSZ21 and UCSZ20 have to be set. YOu only set UCSZ21 and UCSZ20
UCSR2C |= (1<<USBS2) | (1<<UCSZ21) | (1<<UCSZ20);
so I guess that USBS2 is indeed not what you want here. Maybe you were confused because the flag UCSZ22 is in the UCSR2B register.
So assuming you want 9 data bits and one stop bit use something like this:
static void InitializeUART() {
UBRR2L = (uint8_t)(BAUD_PRESCALLER);
UBRR2H = (uint8_t)(BAUD_PRESCALLER>>8);
UCSR2B |= (1 << RXEN2) | (1 << TXEN2) | (1 << UCSZ22);
UCSR2C |= (1 << UCSZ21) | (1 << UCSZ20);
}
Another thing: Your variable data
is of type char
and char is normally 8 bit wide. So the condition if(data & 0x100)
is never satisfied.