In C++ How to detect EOF in arm architecture

Question

f=fopen("/dev/ttyUSB0","r")
char c;
c=getc(f);
while(c!=EOF) {
    c=getc(f);
}

In the code above loop never breaks on beaglebone ubuntu which is arm architecture when I unplug device. The above code worked on my i386 ubuntu desktop.

--EDIT--

Its very weird! Mike's int c; didn't work. Watch on c gives c=255 but even when I changed c!=EOF to c!=255 loop don't break!! I'm very frustrated after trying for an hour!!!

--EDIT--

I tried fstream fin("/dev/ttyUSB0", fstream::in);. when I unplug the input serial device fin>>c never returns and CPU usage is 100%!! I expect its a bug!

Answer 1

Change the type of c from char to int. EOF is outside the range of char.

To clarify, by "change the type", I mean change the declaration to

int c;

not cast the value back to int after truncating it to char.

Answer 2

In C++ it is easier to use cin.

int main()
{
    char ch;

    while (true)
    {
        cin >> ch;
        if (!cin.good())
            break;

        // Do something with you character
    }
}

This will stop when con >> ch fails.