Accessing @MappedSuperclass' properties in Criteria Query using metamodel classes

Question

I'm trying to access a property defined in @MappedSuperclass in a Criteria Query with JPA meta-model (Hibernate 4.2.8):

@MappedSuperclass
public class BaseEntity {
    private DateTime createdOn; 
}

My Entity:

@Entity
@Table(name = "HISTORY")
public class History extends BaseEntity implements Serializable {
    private Long id;
}

How to access createdOn?

CriteriaBuilder cb = getEntityManager().getCriteriaBuilder();
CriteriaQuery<History> c = cb.createQuery(History.class);
Root<History> h = c.from(History.class);
h.orderBy(cb.asc(a.get(History_.createdOn)));

History_:

@Generated(value = "org.hibernate.jpamodelgen.JPAMetaModelEntityProcessor")
@StaticMetamodel(History.class)
public abstract class History_ extends com.test.BaseEntity_ {
public static volatile SingularAttribute<History, Long> id;
}

Is there a way to access base class' properties?

Answer 1

Of course there is a way. As I see in your code, you already access it: History_.createdOn is a property of the MappedSuperclass. If by "to access" you mean to select, than you simply do:

query.select(History_.createdOn)