Overriding default parameters in C# [duplicate]

StackOverflow https://stackoverflow.com/questions/20633980

  •  18-09-2022
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Question

Really simple to replicate, the output is bizarre;

Expected output is "bbb bbb" Actual output is "aaa bbb"

Has anyone got any MSDN explanation of this behaviour? I couldn't find any.

((a)new b()).test();
new b().test();


public class a
{
    public virtual void test(string bob = "aaa ")
    {
        throw new NotImplementedException();
    }
}

public class b : a
{
    public override void test(string bob = "bbb ")
    {
        HttpContext.Current.Response.Write(bob);
    }
}
Was it helpful?

Solution

Why do you expect "bbb bbb"?

Since you are casting the instance to a, the only information to the compiler on the first call is the version with "aaa", so that value is what is used.

In the second version without the cast, the compiler can see the "bbb", so that value is what is used.

Polymorphism impacts which method is invoked - but it doesn't impact the parameters passed. Essentially, the default values are supplied by the compiler (at the call-site), so your code is actually equivalent to:

((a)new b()).test("aaa");
new b().test("bbb");

where the "aaa" and "bbb" is supplied at compile time, by inspection of the resolved method.

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