How do I set the correct compiler to use the -fastsee option

Question

How do I set the correct complier to use the -fastsee option in Fortran? This is the error I'm getting:

Mod5.2.0.0: make -f MakeF90_5.2.0.0
gfortran -fastsse -c src_5.2.0.0/Modtrn.f   -o obj90_5.2.0.0/Modtrn.o
f951: error: unrecognized command line option "-fastsse"
make: * [obj90_5.2.0.0/Modtrn.o] Error 1

Answer 1

-fastsse is an optimisation option of pgf (the Portland Group Fortran Compiler). The executable is typically called pgf90 or pgf95. How to make your build actually use pgf instead of gfortran is specific to build process of the application you are trying to build. (You could try make FC=pgf90, but that is really a stab in the dark. Better inspect the Makefile and/or installation docs.)

Answer 2

man gcc:
...
-msse  -msse2 -msse3 -mssse3 -msse4.1 -msse4.2 -msse4