MySQL Workbench ERROR 1064

Question

I have a problem with my database. I have created the model and now I want to sync it with my database on my WAMP Server (local) but it keeps giving me an error. I searched for the cause of the error for several days. Since I cannot find the problem, I've decided to share it with you.

Message log:

Executing SQL script in server

ERROR: Error 1064: You have an error in your SQL syntax; check the manual
that corresponds to your MySQL server version for the right syntax to use
near ') NULL DEFAULT NULL , n_category VARCHAR(45) NULL DEFAULT NULL ,    
PRIMARY K' at line 3

CREATE TABLE IF NOT EXISTS `telo2p`.`d_category` 
(
  `idd_category` INT(11) NOT NULL AUTO_INCREMENT,
  `f_sells` DOUBLE(11) NULL DEFAULT NULL,
  `n_category` VARCHAR(45) NULL DEFAULT NULL,
  PRIMARY KEY (`idd_category`) 
)
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8
COLLATE = utf8_general_ci

SQL script execution finished: statements: 6 succeeded, 1 failed

Any advice about what I am doing wrong here?

Answer 1

Remove the (11) from the DOUBLE(11):

`f_sells` DOUBLE  NULL DEFAULT NULL ,

Approximate numeric dataypes (Float and Double) need no parameter. There is also a non-standard syntax with 2 parameters. From the MySQL docs, Floating-Point Types (Approximate Value):

MySQL allows a nonstandard syntax: FLOAT(M,D) or REAL(M,D) or DOUBLE PRECISION(M,D). Here, “(M,D)” means that values can be stored with up to M digits in total, of which D digits may be after the decimal point. For example, a column defined as FLOAT(7,4) will look like -999.9999 when displayed. MySQL performs rounding when storing values, so if you insert 999.00009 into a FLOAT(7,4) column, the approximate result is 999.0001.