I can't allocate memory to my char pointer [closed]

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I am trying to just allocate memory to char pointer (its supposed to store hex values later) As soon as i run this code the program crashes. (I have to use C-String)

int main() {
    char *c = (char*)malloc(sizeof(unsigned int)*2);
}

I see this all over the internet as example, but it fails on my machine. Why?

Answer 1

Okay the solution was as easy as the question was supposed to be... I did not see that the .exe file could not be generated and I was therefore running an old .exe file compiled 1hour ago...

Answer 2

Malloc is C, you're trying to do C++.

I would simply do this:

char *c;
c=new char[Max_Size];

Obviously Max_Size would be the size of your intended array.

Answer 3

Try this:

#include <stdlib.h> // for malloc
#include <stdio.h>

int main() {
    char *c = (char*)malloc(sizeof(unsigned int)*2); //It's work

    printf("%d",sizeof(c));

    return 0; // required
}

Answer 4

You did not say what you mean saying that it fails. In any case you have to include header <stdlib.h>

if the program is written in C or <cstdlib> if the program is written in C++.

C code:

#include <stdlib.h>

int main() {
    char *c = (char*)malloc(sizeof(unsigned int)*2);
    free( c );
}

And in any case you should present a code that allows to reproduce the situation. I think that the problem is not in this code but somewhere else where you overwrite memory. The code you showed I think is irrelevant.