Linux - Bash - Get $releasever and $basearch values?

Question

I'm writing a bash script to pull packages from remote repos, using reposync, so I can point my nodes to pull locally. As such I am trying to keep the local repo configs as similar as possible to the usptream repo configs, like this:

# upstream
baseurl=http://mirror.freedomvoice.com/centos/$releasever/os/$basearch/

# local
baseurl=http://user:password@repo.example.com/centos/stable/$releasever/os/$basearch/

Within the bash script, is there a cleaner way to get $releasever and $basearch values? I was thinking of doing the following:

yum_metadata=$(yum version nogroups)

Which returns:

Loaded plugins: versionlock Installed: 6/x86_64 360:6167019baac7e76f94c26320424dc41a7f046a70 version

Then regexing for the 6/x86_64 values. Kind of messy, and looking for a more elegant approach.

Answer 1

Most distro uses the distroverpkg version to get the releasever and basearch.

If you look at /etc/yum.conf, you will see that distrover is set to redhat-release (for RHEL), enterpriselinux-release (for OEL), and others.

To get the package name:

distro=$(sed -n 's/^distroverpkg=//p' /etc/yum.conf)

To get the releasever:

releasever=$(rpm -q --qf "%{version}" -f /etc/$distro)

To get the basearch:

basearch=$(rpm -q --qf "%{arch}" -f /etc/$distro)

The new code above will try to get the package associated with a file /etc/$distro. Some Linux adds /etc/redhat-release to their package release.

If you get file not owned by any package then use the /etc/*-release file that came with your distro. It is probably /etc/centos-release.

You can check the appropriate /etc/*-release appropriate for this code by checking which file is packaged with centos.

rpm -qf /etc/*-release

Then use this file instead of the first line above.

distro=/etc/centos-release

Here's an example from OEL where /etc/redhat-release is packaged as enterprise-release.

rpm -q --qf "%{name}" -f /etc/redhat-release

Output:

enterprise-release