Bash Variable at execution time

Question

There is bash script to setup a cron job .

start.sh :

read -e -p "Enter the path to the log directory: " -i "/home/arya/apps/" LOGPATH
read -e -p "Enter comma separated recepient email-ids:" EMAIL

CURRENT=`pwd` 
COMMAND="python ${CURRENT}/start.sh 2014-08-01T21:12:12 2014-08-01T23:12:12 $LOGPATH  $EMAIL" 
echo $COMMAND   #Here expected output is coming :  */3+1 * * * *  python /home/arya/start.sh 2014-08-01T21:12:12 2014-08-01T23:12:12 /home/arya/apps/utils anilarya280@gmail.com 
cat <(fgrep -i -v "$COMMAND" <(crontab -l)) <(echo "*/3+1 * * * *") | crontab -

This is not taking $CURRENT value in crontab file. Ouput on looking file using crontab -e command:

*/3+1 * * * *         rest things are missing.

Expected output :

  */3+1 * * * *  python /home/arya/start.sh 2014-08-01T21:12:12 2014-08-01T23:12:12 /home/arya/apps/utils anilarya280@gmail.com 

What is problem here?

PLATFORM : UBUNTU 13.04

Answer 1

You need to add the COMMAND variable in the echo to display it.

cat <(fgrep -i -v "$COMMAND" <(crontab -l)) <(echo "*/3+1 * * * * $COMMAND") | crontab -