You can use replacing :
replace \?.*
by \"
If you want to select on the img src link
You can use the following code :
(?<=img src=)[^ ]*\"
then you can replace \?.*
by \"
Question
Am garbing news from out sources, and most of the images are linked to the original source today. My problem, some of the images source link look like this:
<img src="http://www.el-balad.com/upload/photo/news/78/1/360x232o/319.jpg?q=1" width="360"/>
How to use regex in yahoo pipe to make this link to look like this?
<img src="http://www.el-balad.com/upload/photo/news/78/1/360x232o/319.jpg"/>
The thing I need to change is:
.jpg?q=1&w=360&h=150&zc=1
To
.jpg
Solution
You can use replacing :
replace \?.*
by \"
If you want to select on the img src link
You can use the following code :
(?<=img src=)[^ ]*\"
then you can replace \?.*
by \"