Extract part of file name using KornShell

StackOverflow https://stackoverflow.com/questions/4795615

  •  24-10-2019
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Question

I have a file name, for example: xxdatafile_20110120123030_12342.dat. I want to extract "XXdatafile_" from the file name.

How do I do that using Ksh on Unix?

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Solution 

$ file=xxdatafile_20110120123030_12342.dat
$ echo ${file%%_*}
xxdatafile
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