How to write multiple select statement for create table in oracle spatial?

Question 1

I don't know what is oracle Spatial At all. but just by Lookin SQL, I think, the below would work.!

mdsys.sdo_geometry() returns a TYPE sdo_geometry, and it can be used in A SELECT clause multiple times. We do not need to accompany a SELECT every time.

Its is like SELECT B.COMPANY, B.ADDRS,B_CDE .. you don't need to prefix a SELECT always!

General syntax of an SQL could be SELECT <types/columns> FROM <view/table> WHERE <conditions>

create table KP_SPTL(
                            select mdsys.sdo_geometry(
                                                        2003, 
                                                        4326, 
                                                        NULL, 
                                                        SDO_ELEM_INFO_ARRAY(1,3,3), 
                                                        SDO_ORDINATE_ARRAY(B.LL_LAT, B.LL_LON, B.UR_LAT, B.UR_LON)
                                                      ) as KP_GCS,
                              mdsys.sdo_geometry(
                                                        2003, 
                                                        3857, 
                                                        NULL, 
                                                        SDO_ELEM_INFO_ARRAY(1,3,3), 
                                                        SDO_ORDINATE_ARRAY(B.LL_LAT, B.LL_LON, B.UR_LAT, B.UR_LON)
                                                      ) as KP_PCS,
                                                      B.COMPANY, B.ADDRS,B_CDE
                              FROM KP_STAGE B);

Question 2

Your statement will not do what you expect for several reasons.

As I understand, your source table KP_STAGE B contains four columns: LL_LAT, LL_LON, UR_LAT, UR_LON which presumably are the latitude and longitude of the two corners (lower left and upper right) of some rectangle. From what you say, those coordinates are in long/lat WGS84 (i.e. SRID 4326)

And you want a new table that contains two geometry objects, one containing a rectangle in long/lat (SRID 4326), and its equivalent in SRID 3857 (the spherical mercator projection used by Google and others).

There are three problems with your syntax:

1) The order of the ordinates is always X then Y, which for geographic coordinates (latitude/longitude) means they must be specified in longitude first, then latitude. This is the way all GIS systems store geographic data. So use this:

sdo_geometry(
  2003, 4326, NULL, 
  SDO_ELEM_INFO_ARRAY(1,1003,3),                                                          
  SDO_ORDINATE_ARRAY(
    LL_LON, LL_LAT, 
    UR_LON, UR_LAT
  ) 
) as KP_GCS,

2) The element type for a polygon must be one of 1003 or 2003, not just 3. This is so that the database can differentiate between an "outer ring" (= a regular polygon) and a "inner ring" (= a hole).

3) Most important: you cannot construct a geometry in a different coordinate system (in your case 3857) by just setting a different SRID into the spatial object. You need to transform it (project it) to the proper coordinate system using the SDO_CS.TRANSFORM() call, like this:

sdo_cs.transform (
  sdo_geometry(
    2003, 4326, NULL, 
    SDO_ELEM_INFO_ARRAY(1,1003,3),                                                          
    SDO_ORDINATE_ARRAY(
      LL_LON, LL_LAT, 
      UR_LON, UR_LAT
    ) 
  ),
  3857
) as KP_PCS

Note that this will not return a rectangle in the simple two-corner notation: while the result will be graphically rendered as a rectangle, its internal notation is that of a full polygon.

So the full and correct answer will be:

create table KP_SPTL as
select  sdo_geometry (
          2003, 4326, NULL, 
          SDO_ELEM_INFO_ARRAY (1,1003,3),                                                          
          SDO_ORDINATE_ARRAY (
            LL_LON, LL_LAT, 
            UR_LON, UR_LAT
          ) 
        ) as KP_GCS,
        sdo_cs.transform (
          sdo_geometry(
            2003, 4326, NULL, 
            SDO_ELEM_INFO_ARRAY(1,1003,3),                                                          
            SDO_ORDINATE_ARRAY(
              LL_LON, LL_LAT, 
              UR_LON, UR_LAT
            ) 
          ),
          3857
        ) as KP_PCS,
        COMPANY, ADDRS, B_CDE
from KB_STAGE_B;

Or simpler:

create table KP_SPTL as
with t as (
  select  COMPANY, ADDRS, B_CDE,
          sdo_geometry (
            2003, 4326, NULL, 
            SDO_ELEM_INFO_ARRAY (1,1003,3),                                                          
            SDO_ORDINATE_ARRAY (
              LL_LON, LL_LAT, 
              UR_LON, UR_LAT
            ) 
          ) as KP_GCS,
  from KB_STAGE_B
)
select KP_GCS, sdo_cs.transform(KP_GCS, 3857) KP_PCS, COMPANY, ADDRS, B_CDE
from t;