Since Java has checked exception you have to add throws MalformedURLException to your methods header or you have to write the method logic inside try/catch blocks.
MalformedURLException in java application
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06-10-2022 - |
Question
i wrote a simple program which is in my book. but i'm getting the MalformedURLException exception.This is my code
import java.net.URL;
import javax.swing.ImageIcon;
import javax.swing.JOptionPane;
public class ImageGreet{
public static void main(String []args){
URL imageLocation = new URL("http://horstmann.com/java4everyone/duke.gif");
JOptionPane.showMessageDialog(null,"Hello","Title",JOptionPane.PLAIN_MESSAGE,new ImageIcon(imageLocation));
}
}
but my friend said he got it right with the same code. what's wr9ong with my code? Is it because of the internet connection(I'm using a dial-up connection) I
Solution 4
OTHER TIPS
Java uses the concept of checked Exceptions
. You need to put this code inside a try/catch
block, since it is bound to throw a MalformedURLException
. Something like
URL imageLocation = null;
try {
imageLocation = new URL("http://horstmann.com/java4everyone/duke.gif");
} catch (MalformedURLException mue) {
mue.printStackTrace();
}
Or let the main
method throws
the Exception
like :
import java.net.MalformedURLException;
import java.net.URL;
import javax.swing.ImageIcon;
import javax.swing.JOptionPane;
public class ImageGreet{
public static void main(String []args) throws MalformedURLException {
URL imageLocation = new URL("http://horstmann.com/java4everyone/duke.gif");
JOptionPane.showMessageDialog(null,"Hello","Title",JOptionPane.PLAIN_MESSAGE,new ImageIcon(imageLocation));
}
}
catch the MalformedURLException using try and catch block
try {
URL imageLocation = new URL("http://horstmann.com/java4everyone/duke.gif");
JOptionPane.showMessageDialog(null,"Hello","Title",
JOptionPane.PLAIN_MESSAGE,new ImageIcon(imageLocation));
}
catch (MalformedURLException e) {
// new URL() failed
// ...
}
Your internet connection would not cause that Exception. (If your URL did not exist, Java would throw an IOException, probably a FileNotFoundException, per URLConnection documentation.) In fact, your code isn't throwing an Exception at all! What you're seeing is a compile error:
$ javac ImageGreet.java
ImageGreet.java:7: error: unreported exception MalformedURLException; must be caught or declared to be thrown
URL imageLocation = new URL("http://horstmann.com/java4everyone/duke.gif");
^
1 error
When Java tries to turn your program from source code into machine code, it finds a problem, so it stops and asks you to fix it. Your code hasn't run yet -- Java's warning you that there's a problem with your program's source code. (If you're running an IDE, this will show up in a "problems" pane, as opposed to an error message from javac.)
The issue is that you need to catch the MalformedURLException in your code, or declare that main
throws MalformedURLException. For example:
import java.net.URL;
import javax.swing.ImageIcon;
import javax.swing.JOptionPane;
public class ImageGreet{
public static void main(String []args) throws MalformedURLException {
URL imageLocation=new URL("http://horstmann.com/java4everyone/duke.gif");
JOptionPane.showMessageDialog(null,"Hello","Title",JOptionPane.PLAIN_MESSAGE,new ImageIcon(imageLocation));
}
}
Note that I've added throws MalformedURLException
to the end of your main method, which is the latter of the solutions I suggested above. That tells Java that your main method may propagate an Exception of type MalformedURLException.