You could use the string.Split method. In particular I suggest to use the overload that use a string array of possible separators. This because splitting on the newline character poses an unique problem. In you example all the newline chars are simply a '\n', but for some OS the newline char is '\r\n' and if you can't rule out the possibility to have the twos in the same file then
string test = "2345\n564532\n345634\n234 234543\n1324 2435\n";
string[] result = test.Split(new string[] {"\n", "\r\n"}, StringSplitOptions.RemoveEmptyEntries);
Instead if your are certain that the file contains only the newline separator allowed by your OS then you could use
string test = "2345\n564532\n345634\n234 234543\n1324 2435\n";
string[] result = test.Split(new string[] {Environment.NewLine}, StringSplitOptions.RemoveEmptyEntries);
The StringSplitOptions.RemoveEmptyEntries allows to capture a pair of consecutive newline or an ending newline as an empty string.
Now you can work on the array examining the last 3 digits of every string
foreach(string s in result)
{
// Check to have at least 3 chars, no less
// otherwise an exception will occur
int maxLen = Math.Min(s.Length, 3);
string lastThree = s.Substring(s.Length - maxLen, maxLen);
... work on last 3 digits
}
Instead, if you want to work only using the index of the newline character without splitting the original string, you could use string.IndexOf in this way
string test = "2345\n564532\n345634\n234 234543\n1324 2435\n";
int pos = -1;
while((pos = test.IndexOf('\n', pos + 1)) != -1)
{
if(pos < test.Length)
{
string last3part = test.Substring(pos - 3, 3);
Console.WriteLine(last3part);
}
}