Try this:
//return the array and loop through each row
while($row = mysqli_fetch_assoc($result))
{
$adminno = $row['admin_no'];
$name = $row['name'];
$gpa = $row['GPA'];
$gender = $row['gender'];
echo "<tr>";
//changed here (this is called an input array which makes it hold multiple
//values with same name)
echo "<input type='hidden' name='admin_no[]' value='". $adminno ."'/>"; //edited
echo "<td>" . $adminno . "</td>";
echo "<td>" . $name . "</td>";
echo "<td>" . $gpa . "</td>";
echo "<td>" . $gender . "</td>";
//changed here too
echo "<td><select name='ddl[]' >".$options."</select></td>"; //edited
}
In your PHP:
if(isset($_POST['ddl'])){
foreach( $_POST['ddl'] as $index => $val ) //edited extra { here
{
$result4 = mysqli_query($con, "UPDATE `student_details`
SET `company`= '" . $val . "'
WHERE `jobscope1` = 'Information Technology'
AND `admin_no` = '".$_POST['admin_no'][$index]."';");
}
}
In this all your values will be updated (whether you changed any dropdown or not). If you want to limit only the changed dropdowns to be updated then you can have a hidden input variable which changes its value on change of dropdown and update your query only if the hidden input matches.