Groovy XmlSlurper: Find elements in XML structure

Question

Let's say there is the following XML structure:

<Data>
    <DataFieldText>
        <DataFieldName>Field #1</DataFieldName>
        <DataFieldValue>1</DataFieldValue>
    </DataFieldText>
    <DataFieldText>
        <DataFieldName>Field #2</DataFieldName>
        <DataFieldValue>2</DataFieldValue>
    </DataFieldText>
    <DataFieldText>
        <DataFieldName>Field #3</DataFieldName>
        <DataFieldValue>3</DataFieldValue>
    </DataFieldText>
</Data>

Using Groovy's XmlSlurper I need to do the following:

Beginning from Data find that element which contains the value Field #1in the <DataFieldName> element. If found then get the value of the corresponding <DataFieldValue> which belongs to the same level.

Answer 1

If DataFieldName is unique in a file:

println new XmlSlurper()
    .parseText(xml)
    .DataFieldText.find {it.DataFieldName == "Field #1"}
    .DataFieldValue.text()

If it is not, and you want to get an array with all matching DataFieldValues:

println new XmlSlurper()
    .parseText(xml)
    .DataFieldText.findAll {it.DataFieldName == "Field #1"}*.DataFieldValue*.text()

Answer 2

def xml = """<Data>    
    <DataFieldText>    
        <DataFieldName>Field #1</DataFieldName>    
        <DataFieldValue>1</DataFieldValue>    
    </DataFieldText>    
    <DataFieldText>    
        <DataFieldName>Field #2</DataFieldName>     
        <DataFieldValue>2</DataFieldValue>    
    </DataFieldText>    
    <DataFieldText>    
        <DataFieldName>Field #3</DataFieldName>    
        <DataFieldValue>3</DataFieldValue>    
        </DataFieldText>    
</Data>"""      
def payload = new XmlSlurper().parseText(xml)     
def node = payload.'**'.find() { myNode -> myNode.DataFieldName.text() == 'Field #1' }     
value = node.DataFieldValue?.text()    
println "${value}\n"