The 6502 is an 8-bit processor, so you aren't going to be able to calculate 16-bit addresses entirely in registers. You will need to indirect through page zero.
// set $00,$01 to $44AD + 20 * $28 = $47CD
LDA #$CD
STA $00
LDA #$47
STA $01
LDX #20 // Loop 20 times
LDY #0
loop: LDA #$01 // the value to store
STA ($00),Y // store A to the address held in $00,$01
// subtract $28 from $00,$01 (16-bit subtraction)
SEC
LDA $00
SBC #$28
STA $00
LDA $01
SBC #0
STA $01
// do it 19 more times
DEX
BNE loop
Alternatively, you could use self-modifying code. This is a dubious technique in general, but common on embedded processors like the 6502 because they are so limited.
// set the instruction at "patch" to "STA $47CD"
LDA #$CD
STA patch+1
LDA #$47
STA patch+2
LDX #20 // Loop 20 times
loop: LDA #$01 // the value to store
patch:STA $FFFF
// subtract $28 from the address in "patch"
SEC
LDA patch+1
SBC #$28
STA patch+1
LDA patch+2
SBC #0
STA patch+2
// do it 19 more times
DEX
BNE loop